802.11ax RU Allocation Subfield

RU Allocation subfield (B7 B6 B5 B4 B3 B2 B1 B0)	#1	#2	#3	#4	#5	#6	#7	#8	#9	Number of entries
0 (00000000)	26	26	26	26	26	26	26	26	26	1
1 (00000001)	26	26	26	26	26	26	26	52	1
2 (00000010)	26	26	26	26	26	52	26	26	1
3 (00000011)	26	26	26	26	26	52	52	1
4 (00000100)	26	26	52	26	26	26	26	26	1
5 (00000101)	26	26	52	26	26	26	52	1
6 (00000110)	26	26	52	26	52	26	26	1
7 (00000111)	26	26	52	26	52	52	1
8 (00001000)	52	26	26	26	26	26	26	26	1
9 (00001001)	52	26	26	26	26	26	52	1
10 (00001010)	52	26	26	26	52	26	26	1
11 (00001011)	52	26	26	26	52	52	1
12 (00001100)	52	52	26	26	26	26	26	1
13 (00001101)	52	52	26	26	26	52	1
14 (00001110)	52	52	26	52	26	26	1
15 (00001111)	52	52	26	52	52	1
16–23 (00010y₂y₁y₀)	52	52	-	106	8
24–31 (00011y₂y₁y₀)	106	-	52	52	8
32–39 (00100y₂y₁y₀)	26	26	26	26	26	106	8
40–47 (00101y₂y₁y₀)	26	26	52	26	106	8
48–55 (00110y₂y₁y₀)	52	26	26	26	106	8
56-63 (00111y₂y₁y₀)	52	52	26	106	8
64-71 (01000y₂y₁y₀)	106	26	26	26	26	26	8
72-29 (01001y₂y₁y₀)	106	26	26	26	52	8
80-87 (01010y₂y₁y₀)	106	26	52	26	26	8
88-95 (01011y₂y₁y₀)	106	26	52	52	8
96-111 (0110y₁y₀z₁z₀)	106	-	106	16
112 (01110000)	52	52	-	52	52	1
113 (01110001)	242-tone RU empty (with zero users)	1
114 (01110010)	484-tone RU; contributes zero User fields to the User Specific field in the same HE-SIG-B content channel as this RU Allocation subfield	1
115 (01110011)	996-tone RU; contributes zero User fields to the User Specific field in the same HE-SIG-B content channel as this RU Allocation subfield	1
116-119 (011101x₁x₀)	Reserved	4
120-127 (01111y₂y₁y₀)	Reserved	8
128-191 (10y2y1y0z₂z₁z₀)	106	26	106	64
192-199 (11000y₂y₁y₀)	242	8
200-207 (11001y₂y₁y₀)	484	8
208-215 (11010y₂y₁y₀)	996	8
216-223 (11011y₂y₁y₀)	Reserved	8
224-255 (111x₄x₃x₂x₁x₀)	Reserved	32
If signaling RUs of size greater than 242 subcarriers, y₂y₁y₀ = 000–111 indicates the number of User fields in the HE-SIG-B content channel that contains the corresponding 8-bit RU Allocation subfield. Otherwise, y₂y₁y₀ = 000–111 indicates the number of users multiplexed in the 106-tone RU, 242-tone RU or the lower frequency 106- tone RU if there are two 106-tone RUs and one 26-tone RU is assigned between two 106-tone RUs. The binary vector y₂y₁y₀ indicates N_user(r, c) = 2² × y₂ + 2¹ × y₁ + y₀ + 1 users multiplexed in the RU. z₂z₁z₀ = 000–111 indicates the number of users multiplexed in the higher frequency 106-tone RU if there are two 106-tone RUs and one 26-tone RU is assigned between two 106-tone RUs. The binary vector z₂z₁z₀ indicates N_user(r, c) = 2² × z₂ + 2¹ × z₁ + z₀ + 1 users multiplexed in the RU. Similarly, y₁y₀ = 00–11 indicates the number of users multiplexed in the lower frequency 106-tone RU. The binary vector y₁y₀ indicates N_user(r, c) = 2¹ × y₁ + y₀ + 1 users multiplexed in the RU. Similarly, z₁z₀ = 00–11 indicates the number of users multiplexed in the higher frequency 106-tone RU. The binary vector z₁z₀ indicates N_user(r, c) = 2¹ × z₁ + z₀+ 1 users multiplexed in the RU. #1 to #9 (from left to the right) is ordered in increasing order of the absolute frequency. x₁x₀ = 00-11, x₄x₃x₂x₁x₀ = 00000–11111. '-' means no user in that RU, i.e., N_user(r, c) = 0. For RU r that is a 106-tone or larger RU, N_user(r, c) is indicated by the letters (such as y₂y₁y₀ or z₂z₁z₀) in the RU allocation subfield above if the letters are present in the RU allocation subfield; otherwise N_user(r, c) = 0. For RU r that is a 26-tone or 52-tone RU, N_user(r, c) = 1.

0 (00000000)

26

1

1 (00000001)

26

52

1

2 (00000010)

26

52

26

1

3 (00000011)

26

52

1

4 (00000100)

26

52

26

1

5 (00000101)

26

52

26

52

1

6 (00000110)

26

52

26

52

26

1

7 (00000111)

26

52

26

52

1

8 (00001000)

52

26

1

9 (00001001)

52

26

52

1

10 (00001010)

52

26

52

26

1

11 (00001011)

52

26

52

1

12 (00001100)

52

26

1

13 (00001101)

52

26

52

1

14 (00001110)

52

26

52

26

1

15 (00001111)

52

26

52

1

16–23 (00010y₂y₁y₀)

52

-

106

8

24–31 (00011y₂y₁y₀)

106

-

52

8

32–39 (00100y₂y₁y₀)

26

106

8

40–47 (00101y₂y₁y₀)

26

52

26

106

8

48–55 (00110y₂y₁y₀)

52

26

106

8

56-63 (00111y₂y₁y₀)

52

26

106

8

64-71 (01000y₂y₁y₀)

106

26

8

72-29 (01001y₂y₁y₀)

106

26

52

8

80-87 (01010y₂y₁y₀)

106

26

52

26

8

88-95 (01011y₂y₁y₀)

106

26

52

8

96-111 (0110y₁y₀z₁z₀)

106

-

106

16

112 (01110000)

52

-

52

1

113 (01110001)

242-tone RU empty (with zero users)

1

114 (01110010)

484-tone RU; contributes zero User fields to the User Specific field in the same HE-SIG-B content channel as this RU Allocation subfield

1

115 (01110011)

996-tone RU; contributes zero User fields to the User Specific field in the same HE-SIG-B content channel as this RU Allocation subfield

1

116-119 (011101x₁x₀)

Reserved

4

120-127 (01111y₂y₁y₀)

Reserved

8

128-191 (10y2y1y0z₂z₁z₀)

106

26

106

64

192-199 (11000y₂y₁y₀)

242

8

200-207 (11001y₂y₁y₀)

484

8

208-215 (11010y₂y₁y₀)

996

8

216-223 (11011y₂y₁y₀)

Reserved

8

224-255 (111x₄x₃x₂x₁x₀)

Reserved

32

If signaling RUs of size greater than 242 subcarriers, y₂y₁y₀ = 000–111 indicates the number of User fields in the HE-SIG-B content channel that contains the corresponding 8-bit RU Allocation subfield. Otherwise, y₂y₁y₀ = 000–111 indicates the number of users multiplexed in the 106-tone RU, 242-tone RU or the lower frequency 106- tone RU if there are two 106-tone RUs and one 26-tone RU is assigned between two 106-tone RUs. The binary vector y₂y₁y₀ indicates N_user(r, c) = 2² × y₂ + 2¹ × y₁ + y₀ + 1 users multiplexed in the RU.

z₂z₁z₀ = 000–111 indicates the number of users multiplexed in the higher frequency 106-tone RU if there are two 106-tone RUs and one 26-tone RU is assigned between two 106-tone RUs. The binary vector z₂z₁z₀ indicates N_user(r, c) = 2² × z₂ + 2¹ × z₁ + z₀ + 1 users multiplexed in the RU.

Similarly, y₁y₀ = 00–11 indicates the number of users multiplexed in the lower frequency 106-tone RU. The binary vector y₁y₀ indicates N_user(r, c) = 2¹ × y₁ + y₀ + 1 users multiplexed in the RU.

Similarly, z₁z₀ = 00–11 indicates the number of users multiplexed in the higher frequency 106-tone RU. The binary vector z₁z₀ indicates N_user(r, c) = 2¹ × z₁ + z₀+ 1 users multiplexed in the RU.

#1 to #9 (from left to the right) is ordered in increasing order of the absolute frequency.

x₁x₀ = 00-11, x₄x₃x₂x₁x₀ = 00000–11111.

'-' means no user in that RU, i.e., N_user(r, c) = 0.

For RU r that is a 106-tone or larger RU, N_user(r, c) is indicated by the letters (such as y₂y₁y₀ or z₂z₁z₀) in the RU allocation subfield above if the letters are present in the RU allocation subfield; otherwise N_user(r, c) = 0.

For RU r that is a 26-tone or 52-tone RU, N_user(r, c) = 1.